Integrand size = 15, antiderivative size = 127 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=-\frac {a^{10}}{3 x^3}-\frac {4 a^9 b}{x^{5/2}}-\frac {45 a^8 b^2}{2 x^2}-\frac {80 a^7 b^3}{x^{3/2}}-\frac {210 a^6 b^4}{x}-\frac {504 a^5 b^5}{\sqrt {x}}+240 a^3 b^7 \sqrt {x}+45 a^2 b^8 x+\frac {20}{3} a b^9 x^{3/2}+\frac {b^{10} x^2}{2}+210 a^4 b^6 \log (x) \]
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Time = 0.05 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=-\frac {a^{10}}{3 x^3}-\frac {4 a^9 b}{x^{5/2}}-\frac {45 a^8 b^2}{2 x^2}-\frac {80 a^7 b^3}{x^{3/2}}-\frac {210 a^6 b^4}{x}-\frac {504 a^5 b^5}{\sqrt {x}}+210 a^4 b^6 \log (x)+240 a^3 b^7 \sqrt {x}+45 a^2 b^8 x+\frac {20}{3} a b^9 x^{3/2}+\frac {b^{10} x^2}{2} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {(a+b x)^{10}}{x^7} \, dx,x,\sqrt {x}\right ) \\ & = 2 \text {Subst}\left (\int \left (120 a^3 b^7+\frac {a^{10}}{x^7}+\frac {10 a^9 b}{x^6}+\frac {45 a^8 b^2}{x^5}+\frac {120 a^7 b^3}{x^4}+\frac {210 a^6 b^4}{x^3}+\frac {252 a^5 b^5}{x^2}+\frac {210 a^4 b^6}{x}+45 a^2 b^8 x+10 a b^9 x^2+b^{10} x^3\right ) \, dx,x,\sqrt {x}\right ) \\ & = -\frac {a^{10}}{3 x^3}-\frac {4 a^9 b}{x^{5/2}}-\frac {45 a^8 b^2}{2 x^2}-\frac {80 a^7 b^3}{x^{3/2}}-\frac {210 a^6 b^4}{x}-\frac {504 a^5 b^5}{\sqrt {x}}+240 a^3 b^7 \sqrt {x}+45 a^2 b^8 x+\frac {20}{3} a b^9 x^{3/2}+\frac {b^{10} x^2}{2}+210 a^4 b^6 \log (x) \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.98 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=-\frac {2 a^{10}+24 a^9 b \sqrt {x}+135 a^8 b^2 x+480 a^7 b^3 x^{3/2}+1260 a^6 b^4 x^2+3024 a^5 b^5 x^{5/2}-1440 a^3 b^7 x^{7/2}-270 a^2 b^8 x^4-40 a b^9 x^{9/2}-3 b^{10} x^5}{6 x^3}+210 a^4 b^6 \log (x) \]
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Time = 3.52 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.87
method | result | size |
derivativedivides | \(-\frac {a^{10}}{3 x^{3}}-\frac {4 a^{9} b}{x^{\frac {5}{2}}}-\frac {45 a^{8} b^{2}}{2 x^{2}}-\frac {80 a^{7} b^{3}}{x^{\frac {3}{2}}}-\frac {210 a^{6} b^{4}}{x}+45 b^{8} x \,a^{2}+\frac {20 a \,b^{9} x^{\frac {3}{2}}}{3}+\frac {x^{2} b^{10}}{2}+210 a^{4} b^{6} \ln \left (x \right )-\frac {504 a^{5} b^{5}}{\sqrt {x}}+240 a^{3} b^{7} \sqrt {x}\) | \(110\) |
default | \(-\frac {a^{10}}{3 x^{3}}-\frac {4 a^{9} b}{x^{\frac {5}{2}}}-\frac {45 a^{8} b^{2}}{2 x^{2}}-\frac {80 a^{7} b^{3}}{x^{\frac {3}{2}}}-\frac {210 a^{6} b^{4}}{x}+45 b^{8} x \,a^{2}+\frac {20 a \,b^{9} x^{\frac {3}{2}}}{3}+\frac {x^{2} b^{10}}{2}+210 a^{4} b^{6} \ln \left (x \right )-\frac {504 a^{5} b^{5}}{\sqrt {x}}+240 a^{3} b^{7} \sqrt {x}\) | \(110\) |
trager | \(\frac {\left (-1+x \right ) \left (3 b^{10} x^{4}+270 a^{2} b^{8} x^{3}+3 b^{10} x^{3}+2 a^{10} x^{2}+135 a^{8} b^{2} x^{2}+1260 x^{2} a^{6} b^{4}+2 a^{10} x +135 a^{8} b^{2} x +2 a^{10}\right )}{6 x^{3}}-\frac {4 \left (-5 b^{8} x^{4}-180 a^{2} b^{6} x^{3}+378 a^{4} b^{4} x^{2}+60 a^{6} b^{2} x +3 a^{8}\right ) a b}{3 x^{\frac {5}{2}}}+210 a^{4} b^{6} \ln \left (x \right )\) | \(150\) |
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Time = 0.24 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.92 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=\frac {3 \, b^{10} x^{5} + 270 \, a^{2} b^{8} x^{4} + 2520 \, a^{4} b^{6} x^{3} \log \left (\sqrt {x}\right ) - 1260 \, a^{6} b^{4} x^{2} - 135 \, a^{8} b^{2} x - 2 \, a^{10} + 8 \, {\left (5 \, a b^{9} x^{4} + 180 \, a^{3} b^{7} x^{3} - 378 \, a^{5} b^{5} x^{2} - 60 \, a^{7} b^{3} x - 3 \, a^{9} b\right )} \sqrt {x}}{6 \, x^{3}} \]
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Time = 0.29 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.01 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=- \frac {a^{10}}{3 x^{3}} - \frac {4 a^{9} b}{x^{\frac {5}{2}}} - \frac {45 a^{8} b^{2}}{2 x^{2}} - \frac {80 a^{7} b^{3}}{x^{\frac {3}{2}}} - \frac {210 a^{6} b^{4}}{x} - \frac {504 a^{5} b^{5}}{\sqrt {x}} + 210 a^{4} b^{6} \log {\left (x \right )} + 240 a^{3} b^{7} \sqrt {x} + 45 a^{2} b^{8} x + \frac {20 a b^{9} x^{\frac {3}{2}}}{3} + \frac {b^{10} x^{2}}{2} \]
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Time = 0.20 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.87 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=\frac {1}{2} \, b^{10} x^{2} + \frac {20}{3} \, a b^{9} x^{\frac {3}{2}} + 45 \, a^{2} b^{8} x + 210 \, a^{4} b^{6} \log \left (x\right ) + 240 \, a^{3} b^{7} \sqrt {x} - \frac {3024 \, a^{5} b^{5} x^{\frac {5}{2}} + 1260 \, a^{6} b^{4} x^{2} + 480 \, a^{7} b^{3} x^{\frac {3}{2}} + 135 \, a^{8} b^{2} x + 24 \, a^{9} b \sqrt {x} + 2 \, a^{10}}{6 \, x^{3}} \]
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Time = 0.27 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.87 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=\frac {1}{2} \, b^{10} x^{2} + \frac {20}{3} \, a b^{9} x^{\frac {3}{2}} + 45 \, a^{2} b^{8} x + 210 \, a^{4} b^{6} \log \left ({\left | x \right |}\right ) + 240 \, a^{3} b^{7} \sqrt {x} - \frac {3024 \, a^{5} b^{5} x^{\frac {5}{2}} + 1260 \, a^{6} b^{4} x^{2} + 480 \, a^{7} b^{3} x^{\frac {3}{2}} + 135 \, a^{8} b^{2} x + 24 \, a^{9} b \sqrt {x} + 2 \, a^{10}}{6 \, x^{3}} \]
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Time = 5.76 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.88 \[ \int \frac {\left (a+b \sqrt {x}\right )^{10}}{x^4} \, dx=\frac {b^{10}\,x^2}{2}-\frac {\frac {a^{10}}{3}+\frac {45\,a^8\,b^2\,x}{2}+4\,a^9\,b\,\sqrt {x}+210\,a^6\,b^4\,x^2+80\,a^7\,b^3\,x^{3/2}+504\,a^5\,b^5\,x^{5/2}}{x^3}+420\,a^4\,b^6\,\ln \left (\sqrt {x}\right )+45\,a^2\,b^8\,x+\frac {20\,a\,b^9\,x^{3/2}}{3}+240\,a^3\,b^7\,\sqrt {x} \]
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